<!DOCTYPE html>
<html>

	<head>
		<meta charset="UTF-8">
		<title></title>
		<style>
.siblings *{ 
	display: block;
	border: 2px solid lightgrey;
	color: lightgrey;
	padding: 5px;
	margin: 15px;
}
</style>
		<!--[if lt IE 9]>
    <script src="jquery-1.9.0.js"></script>
<![endif]-->
		<!--[if gte IE 9]><!-->
		<script src="https://code.jquery.com/jquery-3.1.1.min.js"></script>
		<!--<![endif]-->
		<script type="text/javascript">
$(document).ready(function(){
	$("li.start").nextAll().css({"color":"red","border":"2px solid red"});
});
		</script>
	</head>

	<body>

<div style="width:500px;" class="siblings">
	<ul>ul (父节点)  
		<li>li (兄弟节点)</li>
		<li>li (兄弟节点)</li>
		<li class="start">li (类名为“star”的兄弟节点)</li>
		<li>li (类名为“star”的li节点的下一个兄弟节点)</li>
		<li>li (类名为“star”的li节点的下一个兄弟节点)</li>
		<li>li (类名为“star”的li节点的下一个兄弟节点)</li>
	</ul>   
</div>
<p>在这个例子中,我们将返回类名为“star”的li节点的所有下一个兄弟节点。</p>

	</body>
</html>